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Re: Question G4Scintillation - optical photon generation (Bruno Arsenali)
Re: None Re: G4Scintillation - optical photon generation (Bruno Arsenali)
Date: 08 Jun, 2012
From: Gumplinger Peter <Gumplinger Peter>

> But the thing that I don't understand is that if I look at step 'Delta
> energy'
> step->GetPreStepPoint()->GetTotalEnergy()-step->GetPostStepPoint()->GetTotalEnergy()
> I can see that it is 122keV (for scintillation step). Also I can see
> that after that step gamma ray stops, because her energy is 122keV and
> in that step she lost all of her energy.
> 
> Base on that I don't understand what happened with the rest of energy
> (122keV-33keV). I would expect that all energy should be converted to
> photons. In other words I would like to get 1220 photons from
> scintillation if gamma ray lose 122 keV.
> 
> Can You please be so kind give me explanation or further direction on
> how to solve my problem?

Your 122keV gamma undergoes the photo electric effect with the ejection of an electron with kin. energy: 122keV-33keV. (the step is limited by that process). You also have a production cut that is below that value and so the photo electron is put on the tracking stack to be tracked (probably next in your event). This electron will then lose its kin. energy in your detector, or only part of it, and so energy will 'leak out' of your detector. If it too stops in your detector, then you'll get all of the original 122keV deposited and the total number of photons generated in the event will be the one you expect. Trust me!

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1 None: Re: G4Scintillation - optical photon generation   (Bruno Arsenali - 09 Jun, 2012)
2 None: Re: G4Scintillation - optical photon generation   (Cejo George - 15 Jun, 2012)
1 Feedback: Re: G4Scintillation - optical photon generation   (Gumplinger Peter - 15 Jun, 2012)
2 None: Re: G4Scintillation - optical photon generation   (Bruno Arsenali - 15 Jun, 2012)
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