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Re: transmission probabily in optical surface

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Re: transmission probabily in optical surface (Meiling Yu)
Re: Re: transmission probabily in optical surface (Gumplinger Peter)
Re: Re: transmission probabily in optical surface (Meiling Yu)
Date: 16 Jul, 2004
From: Craig Hourie <chourie@trentu.ca>

 Hello just a little side note here: //Hi, I'm trying to convert the transmission probability to absorption length. Suppose the glass thickness is g, absorption length is l, transmission probability is p, then their relation is //p=exp(-g/l) I think that this is correct also. //When I apply it to my program, here g=1*cm, number of photons is around 2000, for the case l=10*m which means p~1, I have the number of absorbed photons is 0, but when l=0.05*cm i.e.p~0, the number of absorbed photons is only about 60, which seems too small compared to 2000 photons! I believe that the l value of 0.05*cm is the absorption length in NaI(Tl). One of the great advantages of NaI(Tl) is that it is virtually transparent to its own emmission bands, characterized by its high stokes shift due to its Thallium activation centers. This means that there will be very little optical absorption within the crystal. I have been using the same values in my simulation. //Is my way to relate transmission probability with absorption length wrong? Nope ;) //Many thanks //Meiling Yu Cheers, Craig Hourie

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