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None Scintillator detector efficiency 

Forum: Processes Involving Optical Photons
Date: 04 Sep, 2010
From: Davinder Siwal <Davinder Siwal>

Hiii geant4 users

I would like to calculate the intrinsic detection efficiency of neutron scintillator detector, in case of gamma detector i know that it is simply the ratio of no. of events interacted to the no. of events incident does the same thing is true for neutron detector????

to start with i have seen the N06 example but i don't understand the following entries

 const G4int nEntries = 32;

  G4double PhotonEnergy[nEntries] =
            { 2.034*eV, 2.068*eV, 2.103*eV, 2.139*eV,
              2.177*eV, 2.216*eV, 2.256*eV, 2.298*eV,
              2.341*eV, 2.386*eV, 2.433*eV, 2.481*eV,
              2.532*eV, 2.585*eV, 2.640*eV, 2.697*eV,
              2.757*eV, 2.820*eV, 2.885*eV, 2.954*eV,
              3.026*eV, 3.102*eV, 3.181*eV, 3.265*eV,
              3.353*eV, 3.446*eV, 3.545*eV, 3.649*eV,
              3.760*eV, 3.877*eV, 4.002*eV, 4.136*eV };
//
// Water
//	      
  G4double RefractiveIndex1[nEntries] =
            { 1.3435, 1.344,  1.3445, 1.345,  1.3455,
              1.346,  1.3465, 1.347,  1.3475, 1.348,
              1.3485, 1.3492, 1.35,   1.3505, 1.351,
              1.3518, 1.3522, 1.3530, 1.3535, 1.354,
              1.3545, 1.355,  1.3555, 1.356,  1.3568,
              1.3572, 1.358,  1.3585, 1.359,  1.3595,
              1.36,   1.3608};

  G4double Absorption1[nEntries] =
           {3.448*m,  4.082*m,  6.329*m,  9.174*m, 12.346*m, 13.889*m,
           15.152*m, 17.241*m, 18.868*m, 20.000*m, 26.316*m, 35.714*m,
           45.455*m, 47.619*m, 52.632*m, 52.632*m, 55.556*m, 52.632*m,
           52.632*m, 47.619*m, 45.455*m, 41.667*m, 37.037*m, 33.333*m,
           30.000*m, 28.500*m, 27.000*m, 24.500*m, 22.000*m, 19.500*m,
           17.500*m, 14.500*m };

  G4double ScintilFast[nEntries] =
            { 1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00,
              1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00,
              1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00,
              1.00, 1.00, 1.00, 1.00, 1.00, 1.00, 1.00,
              1.00, 1.00, 1.00, 1.00 };
  G4double ScintilSlow[nEntries] =
            { 0.01, 1.00, 2.00, 3.00, 4.00, 5.00, 6.00,
              7.00, 8.00, 9.00, 8.00, 7.00, 6.00, 4.00,
              3.00, 2.00, 1.00, 0.01, 1.00, 2.00, 3.00,
              4.00, 5.00, 6.00, 7.00, 8.00, 9.00, 8.00,
              7.00, 6.00, 5.00, 4.00 };

does anybody knows the answer

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1 None: Re: Scintillator detector efficiency   (Randolph Moellenberg - 09 Sep, 2010)
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