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Feedback Re: SCINTILLATIONYIELD and number of photons 

Keywords: SCINTILLATIONYIELD, number of photons
Forum: Processes Involving Optical Photons
Date: 27 Sep, 2007
From: Gumplinger Peter <Gumplinger Peter>

Hello Xinhua,

Before we look at the number of photos produced, could you make a histogram of the energy deposition in your scintillator. Is the MPV, as you expect 4MeV? For all the scintillation process does is:

        ScintillationYield = YieldFactor * ScintillationYield;
        MeanNumberOfPhotons = ScintillationYield * TotalEnergyDeposit;

        if (MeanNumberOfPhotons > 10.) {
          G4double sigma = ResolutionScale * sqrt(MeanNumberOfPhotons);
          NumPhotons = G4int(G4RandGauss::shoot(MeanNumberOfPhotons,sigma)+0.5);        }
        else {
          NumPhotons = G4int(G4Poisson(MeanNumberOfPhotons));
        }

This is assuming you have set the YieldFactor and the ResolutionScale:

theScintillationProcess->SetScintillationYieldFactor(1.);

and

AddConstProperty("RESOLUTIONSCALE", 1.0);

in your program.

If you don't get 4MeV try standard EM physics.

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