|Message: Re: how to calculate the detector efficiency?||Not Logged In (login)|
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User T.P.Lee wrote:
>> I still have some confuse with it. the detector efficiency, in my case >> ,means the number of events absorbed and divide with the number of >> events incident on the absorber. This is based from the book by Glenn F. >> Knoll, Radiation Detection and measurement. So I think I need get the >> number of events absorbed by the absorber( that is a BGO crystal). but i >> don't know how to do it. >> >> when one particle enters the BGO crystal, there are some possibility, >> one is it pass through the crystal, and another is it loses its total >> energy and is absorbed by the crystal. It appears clearly for me I >> should count the latter case. but how to know one particle lose its >> total energy after it enter the BGO? >> >> thanks for your help
There are not 2 but 3 cases, depending of the thickness of the crystal: 1- the incident gamma does not interact in the crystal 2- the incident gamma interact, but only a fraction of its energy is deposited 3- all its energy is deposited.
What is the thickness of your crystal ?
a)You can measure the total energy deposit in the crystal. See examples/novice/N03 or examples/extended/electromagnetic/TestEm3
b) on the opposite you can measure the energy leakage. See TestEm2
If you are interested only by: the incident gamma interacts or not, you can check that this primary gamma leaves, or not, the BGO. Some examples of this are in TestEm5 (although it can be simplified..)
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