|Message: Re: Energy Conservation Problem||Not Logged In (login)|
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> > It is true that using this example, 150 MeV are deposited, but this is > because there is no inelastic hadronic interaction simulated. By adding > such processes in the simulation (/testem/phys/addPhysics binary), then > there is some missing energy. > > The run consists of 10000 proton of 150 MeV through 40 cm of G4_WATER (density: 1 g/cm3 ) > > Projected Range= 14.5021 cm rms= 3.54837 cm > Mean number of primary steps = 25.0488 > Total energy deposit= 144.758 MeV > niel energy deposit = 413.432 eV >
May I suggest you to send a mail to forum hadronic processes.
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