|Message: Re: Spin tracking of muons at rest||Not Logged In (login)|
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On Thu, 19 Feb 2009 00:30:27 GMT, Gumplinger Peter wrote:
> > can you point out how the code in the distribution ensures > > > the G4DecayWithSpin terms don't come in to play for moving muons? > > (see above) > > rotationangle = fRemainderLifeTime * omega = 0. * omega > > You can verify that fRemainderLifeTime has already been updated (reduced > to zero) by the time the G4DecayWithSpin::DecayIt is called for a decay > in flight. > > Peter >
This is the key point I was missing; now that I understand it, the rest of the code makes perfect sense. Thanks again for your help.