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Forum: Analysis
Re: None Replica and energy density deposition (Olivier Dadoun)
Re: None Re: Replica and energy density deposition (michel maire)
Date: 09 Jul, 2009
From: Olivier Dadoun <Olivier Dadoun>

Hello Michel,

I have a Tungsten target of 2.5cm*2.5cm*1.2cm.

I use for exemple 100 MeV of e- beam energy to impinge on this target (normal incidence with a gaussian spatial distribution in X and Y with a sigma of 1.6mm).

If took 0.025*0.025*0.012cm3 as elementary volume:

I found a maximum energy of 8.41 MeV, so 8.41/(0.025*0.025*0.012)=1.1e6MeV/cm3,

If I took 0.05*0.05*0.024cm3 as elementary volume:

I found a maximum energy of 27.4 MeV, so 27.4/( 0.05*0.05*0.024)=4.56e5MeV/cm3.

There is 60% of difference between maximum energy density.

Thank you Olivier

PS:I will have a look on TestEm2 and TestEm11.

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1 None: Re: Replica and energy density deposition   (michel maire - 10 Jul, 2009)
(_ None: Re: Replica and energy density deposition   (Olivier Dadoun - 12 Jul, 2009)
(_ None: Re: Replica and energy density deposition   (michel maire - 15 Jul, 2009)
(_ None: Re: Replica and energy density deposition   (Olivier Dadoun - 21 Jul, 2009)
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