|Message: Re: Replica and energy density deposition||Not Logged In (login)|
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I have a Tungsten target of 2.5cm*2.5cm*1.2cm.
I use for exemple 100 MeV of e- beam energy to impinge on this target (normal incidence with a gaussian spatial distribution in X and Y with a sigma of 1.6mm).
If took 0.025*0.025*0.012cm3 as elementary volume:
I found a maximum energy of 8.41 MeV, so 8.41/(0.025*0.025*0.012)=1.1e6MeV/cm3,
If I took 0.05*0.05*0.024cm3 as elementary volume:
I found a maximum energy of 27.4 MeV, so 27.4/( 0.05*0.05*0.024)=4.56e5MeV/cm3.
There is 60% of difference between maximum energy density.
Thank you Olivier
PS:I will have a look on TestEm2 and TestEm11.
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